50x^2+15x-2=(10x-1)

Solution for 50x^2+15x-2=(10x-1) equation:

50x^2+15x-2=(10x-1)

We move all terms to the left:

50x^2+15x-2-((10x-1))=0


We calculate terms in parentheses: -((10x-1)), so:

(10x-1)

We get rid of parentheses

10x-1

Back to the equation:

-(10x-1)


We get rid of parentheses

50x^2+15x-10x+1-2=0

We add all the numbers together, and all the variables

50x^2+5x-1=0

a = 50; b = 5; c = -1;
Δ = b2-4ac
Δ = 52-4·50·(-1)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-15}{2*50}=\frac{-20}{100}
=-1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+15}{2*50}=\frac{10}{100}
=1/10
$